How to interpret fold-changes when the sample purity is not 100%

If your sample purity is less than 100%, it is necessary to take that into account when interpreting the fold-change values. Given a sample purity of $ X$%, and an amplification with an observed fold-change of $ F$, the following formula gives the actual fold-change that would be seen if the sample were 100% pure:

fold-change in 100% pure sample$\displaystyle = \frac{F - 1}{X / 100\text{\%}} + 1$

For example, if the sample purity is 40%, and you have observed an amplification with a fold-change of 3, then the fold-change in the 100% pure sample would have been:

fold-change in 100% pure sample$\displaystyle = \frac{3.0 - 1}{40\text{\%} / 100\text{\%}} + 1 = 6.0.$

For a deletion the formula for converting an observed (absolute) fold-change to the actual (absolute) fold change is:

fold-change in 100% pure sample$\displaystyle = \frac{F \times X / 100\text{\%}}{1 - F \times (1 - X / 100\text{\%})}$

For example, if the sample purity is 40%, and you have a deletion with an absolute fold-change of 1.25, then the absolute fold-change in the 100% pure sample would have been:

fold-change in 100% pure sample$\displaystyle = \frac{1.25 \times 40 / 100\text{\%}}{1 - 1.25 \times (1 - 40 / 100\text{\%})} = 2.0.$

Figures 32.27 and 32.28 shows the 'true' fold changes for different observed fold-changes at different sample purities.

Image observed_to_true_conversion_amp
Figure 32.27: The true amplification fold-change in the 100% pure sample, for different observed fold-changes, as a function of sample purity.

Image observed_to_true_conversion_del
Figure 32.28: The true deletion fold-change in the 100% pure sample, for different observed fold-changes, as a function of sample purity.